Question

What is the oxidation state of sulphur in H2 S2 O6​

Answer 1

Answer:

+5

Explanation:

2(+1)+ 2S +6(-2) =0

2+2S-12=0

2S=10

S=+5

Answer 2

Given: The given compound is $H_2S_2O_6$.

To find: We have to find the oxidation state of Sulfur.

Solution:

The given compound is $H_2S_2O_6$.

Let the oxidation state of sulfur be x.

The charge of H is +1 and the charge of Oxygen is -2.

The compound is neutral so, the overall oxidation state is 0.

So, we can write-

$2 \times ( + 1) + 2x + 6 \times ( - 2) = 0 \\ + 2 + 2x - 12 = 0 \\ 2x = 10 \\ x = + 5$

The value of x is +5.

So, the oxidation state of Sulfur is +5.