Question

what is the oxidation state of vanadium in the compound NH4vo3 a.-1;b.+1;c.+3;d.+5​

Answer 1

Answer:it is +5

Explanation:as the amonium(nh4)s oxidation state is constant and equals to +1 so VO3 should be -1. And O 's is -2

3x-2 is -6 so to reach -1 ,V should have an oxidation state of +5

Answer 2

The correct option is d.

• The charge of the N atom is -3.
• The charge of the Oxygen atom is -2.
• The charge of a hydrogen atom is +1.
• The compound is neutral so the overall charge is zero.
• Let oxidation state of V is x.
• Thus we can write-
• $- 3 + 4 + x - 6 = 0 \\ x = + 5$
• The value of x is +5.
• Thus oxidation state of V is +5.