Question

what is the oxidation state of xenon in the following compound XeF2???explain in detail​

Answer 1

Answer:

The oxidation state of xenon in Xenon Difluoride is +2.

Answer 2

Answer:

O.S=+2of xenon .

Explanation:

let us take oxidation state of Xe be x.

Now,

since, wkt oxidation state of F (flourine) is -1.

therefore , F2 becomes -1 *2 =-2.

now, by adding oxidation state of both Xe and F we get, x+(-2)=0=> x-2=0=> x=+2.

Hence, O.S ( oxidation state ) of Xe (xenon) is +2.