what is the packing fraction of simple cubic unit cell derivation
Answers
Answered by
1
Answer:
74%
Explanation:
Packing efficiency (P.E.) =
V
n×
3
4
πr
3
×100
For a FCC lattice, n=4
Therefore, P.E. =
a
3
4×
3
4
×(
2
2
a
3
)
=
3
2
π
×100=74%
Hence. in FCC, 74% of the total volume is occupied by atoms.
Answered by
3
Answer :-
74 %
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