Question

What is the pair of numbers whose product is 64 and whose sum is 20

Answer 1

Answer:+=20⟹=20−

a

+

b

=

20

⟹

a

=

20

−

b

×=(20−)×=20−2

a

×

b

=

(

20

−

b

)

×

b

=

20

b

−

b

2

Ok

20−2=64∣⟺

20

b

−

b

2

=

64

∣

⟺

2−20+64=0 ∣ complete the square

b

2

−

20

b

+

64

=

0

∣

complete the square

(−10)2−100+64=0∣+36

(

b

−

10

)

2

−

100

+

64

=

0

∣

+

36

(−10)2=36∣√

(

b

−

10

)

2

=

36

∣

−10=±6∣+10

b

−

10

=

±

6

∣

+

10

=16∨4

b

=

16

∨

4

=20−16=4∨20−4=16

a

=

20

−

16

=

4

∨

20

−

4

=

16

The numbers are 4

4

and 16

16

.

16+4=20

16

+

4

=

20

16×4=64

Step-by-step explanation:

Answer 2

Answer:

16 and 4.

16 × 4 = 64

16 + 4 = 20

Please mark brainliest if it helps :)

Here is a more complex explanation