Question

what is the path travelled by an object when it is thrown from ground at a height h

Answer 1

hey !!

In this case we will use second equation of motion S=ut+(1/2)at^2

where, s= distance travelled (height)

u= initial velocity(here u=0)

a= acceleration due to gravity (9.8m/s^2)

t= time taken

s = 0×10 + (1/2)×9.8×10×10

= 980/2 = 490m

Equations of motion are valid only when acceleration is constant and motion is constrained to a straight line.