Question

what is the percent by mass of 5.0g of iron (II)sulphate dissolved 75.0g of water​

Answer 1

The % is

5/75 * 100 = 20/3%

That is 6.66666667 %

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Answer 2

Answer:

6.25%

Explanation:

solute= 5g

solution= 75+5=80g

$\frac{5}{80} \times 100 = \frac{25}{4 } = 6.25$

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