Question

What is the percent by mass of C6H12O6 in a solution 45 g of C6H12O6, dissolved in 800 g of water​

Answer 1

(i) Total mass of solution

=5.64+60=65.64g

Mass percent of glucose =

65.64

5.64

×100=8.59%

Mass per cent of water =(100−Mass per cent of glucose)

=(100−8.59)=91.41%

(ii) No. of moles of glucose =

180

5.64

Mass of water in kg =

1000

60

Molality =

180

5.64

×

60

1000

=0.522m

(iii) No. of moles of glucose =

180

5.64

=0.0313

No. of moles of water =

18

60

=3.333

Mole fraction of glucose =

3.333+0.0313

0.0313

=0.0093

Mole fraction of water =

3.333+0.0313

3.333

=0.9907