Question

What is the percent by mass of sodium in Na2SO4? Use mc028-1.jpg (A) 16.18% (B) 22.58% (C) 32.37% (D) 45.98%

Answer 1

Answer:- C) 32.37%

Solution:- The given compound has two Na, one S and four O.

mass of Na = 2(22.99) = 45.98

mass of S = 1(32.06) = 32.06

mass of O = 4(16) = 64

molar mass of the compound = 45.98 + 32.06 + 64 = 142.04

percent by mass of Na = $(\frac{mass of Na}{molar mass of Na_2SO_4})100$

Let's plug in the values in the formula:

percent by mass of Na = $(\frac{45.98}{142.04})100$

= 32.37%

So, the percent by mass of Na in $Na_2SO_4$ is 32.37%.

Answer 2

Answer: 32.37, the answer should show even with the brainly plue ad blocking it, hope this helps:)

Explanation: i just took the test