What is the percent by mass of sugar solution prepared by dissolving 12 grams of sucrose(table sugar)in84 grams of solution
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1
Answer:
DepressioninFreezingpointΔT
f = M 1 ×W 2
W 1 ×K f ×1000
where W 1 =Weight of Solute
W 2 =Weight of solvent
M 1 =Molar mass of solute
K f =Freezing point deprssion constant
Now,ΔT f= 342×1000
1.86×68.5×1000
=0.372C
Now,ΔT f =T o −T f
So,T f =0−0.372=−0.372C.
(Freezing point of purewater=0
0
C.)
Hence, the correct option is A
Answered By : Tanisha
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