What is the percent potassium, chromium, and oxygen in K2Cr2O7?
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Answer:
K2Cr2O7 is 26.58%K, 35.35%Cr AND 38.07% O by mass.
Explanation:
The formula of percent composition is
% by mass = mass of component / mass of sample *100%
we have to find the mass of K, Cr, and O in a given mass of a compound .
Mass of K = 2 × 39.10 g = 78.20 g
Mass of Cr = 2 × 52.00 g = 104.00 g
Mass of O = 7 × 16.00 g = 112.00 g
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Mass of K2Cr2O7 = 294.20 g
∴ % K = mass of K /mass of K2Cr2O7 *100%
=78.20 g / 294.20 g *100% =26.58%
% Cr = mass of Cr/ mass of K2Cr2O7 *100% =104.00 g/294.20 g *100%
=35.35%
% O = mass of O / mass of K2Cr2O7 *100% =112.00 g/294.20 g *100%
= 38.07 %
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