What is the percentage by mass of sodium in sodium hydroxide.(Na=23,O=16,H=1).please show workings
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The Atomic Number of Elements are: H = 1 g, Na = 23 g, O = 16 g.
Given the Compound = Sodium Hydroxide (NaOH)
Molar Mass = (23+16+1) g
= 40 g
% composition of Na in NaOH = (23/40)*100 %
= 57.5%
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Answer:
Explanation:
What is the percentage by mass of sodium in sodium hydroxide Na=23, O=16, H=1
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