What is the percentage change in length of 4m iron rod if its temperature changes by 200°C.
(a iron = 2 x 10^-5/°C)
O 0.2%
O 0.4%
O 0.6%
O 0.5%
Answers
We have to find the percentage change in length of 4m iron rod if its temperature changes by 200°C. coefficient of iron is 2 × 10¯⁵/°C.
solution : change in length is given by, ∆L = L₀α∆T
⇒fractional change = ∆L/L₀ = α∆T
⇒percentage change = ∆L/L₀ × 100 = 100α∆T
here α = 2 × 10¯⁵/°C and ∆T = 200°C
so, percentage change in length of iron rod = 100 × 2 × 10¯⁵ × 200
= 4 × 10⁴ × 10¯⁵ = 0.4 %
Therefore the correct option is (B) 0.4 %
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