Question

What is the percentage decrease in the weight of a body when taken to depth of 1km below the surface of earth. ​

Answer 1

0.016 %

Explanation:

Here, d=32km; R=6400km

Weight of body at depth d is =mg′

=mg[1−(d/R)]

% decrease in weight = (mg−mg′)/mg

=(d/R)×100

= (1/6400)×100=(1/64)

= 0.016 %