What is the percentage error in the measurements of the kinetic energy of the body, if there is a positive error of 50./. In the speed of a body
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Answered by
4
Given that,
v
Δv
×100 is the % error in velocity = 50%
Kinetic energy K.E=
2
1
mv
2
Error in the kinetic energy
K.E
ΔK.E
×100=m×2
v
Δv
×100
m is as a constant
Now, percentage error
K.E
ΔK.E
×100=2
v
Δv
×100
K.E
ΔK.E
×100=2×50%
K.E
ΔK.E
×100=100%
Hence, the error in the measurement of kinetic energy is 100%
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2
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