Math, asked by Nicole6664, 1 year ago

What is the percentage error in volume of a sphere when error in measuring its radius is 0.2℅?

Answers

Answered by Divesh2409200
0
percentage error in volume is 0.6%
answer may help you
Answered by Anonymous
2

\huge\textbf{Answer}


V = 4/3 πr³ [Volume of sphere]

∆V/V = ± 3 (∆r/r)

∆V/V = ± (3 × 0.2)

∆V/V = ± 0.6%


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