What is the percentage error in volume of a sphere when error in measuring its radius is 0.2℅?
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percentage error in volume is 0.6%
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V = 4/3 πr³ [Volume of sphere]
∆V/V = ± 3 (∆r/r)
∆V/V = ± (3 × 0.2)
∆V/V = ± 0.6%
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