Question

What is the percentage hydrolysis of NaCN in N/80 solution when the dissociation constant for HCN is 1.3*10^-9 and Kw=1*10^-14

Answer 1

Solution-

given

ka=1.3*10^-9

kw=1*10^-4

n=n/80

h=√kn/c =√kw/√ka*c

h=√10*80/√1.3*10^9*1

h=2.48%. answers.

The  percentage of hydrolysis of nacn in n/80 solution when the dissociation constant  for hcn  is 2.48%.

Here is the answer hope this answer helps you and helps you clear all the doubts..

Answer 2

Explanation:

so this is the correct answer