Question

what is the percentage of carbon hydrogen and oxygen in acetic acid (CH3 COOH)​

Answer 1

Answer:

The percent composition of carbon in acetic acid is 40.002% .

Answer 2

Answer:

$\bigstar{\bold{Percentage\:composition\:of\:carbon=40\%}}$

$\bigstar{\bold{Percentage\:composition\:of\:hydrogen=6.67\%}}$

$\bigstar{\bold{Percentage\:composition\:of\:oxygen=53.33\%}}$

Explanation:

$\Large{\underline{\bf{Given:}}}$

• Acetic acid (CH₃COOH)

$\Large{\underline{\bf{To\:Find:}}}$

• The percentage composition of carbon , hydrogen and oxygen present in acetic acid.

$\Large{\underline{\bf{Solution:}}}$

➛ First we have to find the molar mass of acetic acid.

    Molar mass of CH₃COOH = 12 + 3 + 12 + 16 + 16 + 1

    Molar mass of CH₃COOH = 60 g

Percentage of carbon:

➛ The percentage composition of carbon is given by,

    Percentage composition of carbon = Molar mass of carbon in the compound/Total molar mass of compund × 100

➛ Molar mass of carbon = 12 g

➛ Substitute the data,

   Percentage composition of carbon = 12 × 2 /60 × 100

   Percentage composition of carbon = 24/60 × 100

  Percentage composition of carbon = 40 %

   $\boxed{\bold{Percentage\:composition\:of\:carbon=40\%}}$

Percentage composition of hydrogen:

➛ Percentage composition of hydrogen = Molar mass of hydrogen in the compound/Total molar mass of compund × 100

➛ Molar mass of hydrogen = 1g

➛ Substituting the data,

    Percentage composition of hyrogen = 4/60 × 100

    Percentage composition of hydrogen = 6.67 %

    $\boxed{\bold{Percentage\:composition\:of\:hydrogen=6.67\%}}$

Percentage composition of oxygen:

➛Percentage composition of oxygen = Molar mass of oxygen in the compound/Total molar mass of compund × 100

➛ Molar mass of oxygen = 16 g

➛ Substituting the data,

    Percentage composition of oxygen = 16 × 2/60 × 100

    Percentage composition of oxygen = 53.33 %

    $\boxed{\bold{Percentage\:composition\:of\:oxygen=53.33\%}}$