what is the percentage of getting a red ball if i have 182 red ball and 189 green ball
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5White 6Red 9Green
Total number of balls =5+6+9
=20
(i) Probability =Total casesfavourable cases
P(Green) =209
(ii) P(White or red) =205+6
=2011
(iii) P(neither green nor white) = P(Red)
=206
=103
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