What is the percentage of light reduced in benzene?
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Let c be speed of light in vaccum and v be speed of light in benzene.
Refractive index of benzene=1.5=speed of light in vaccum/speed of light in benzene.
c/v=1.5. v=2/3c
Percentage reduce in speed of light=(c-v/c)*100
=(1/3)*100=33.33%
it may be correct r wrong
Refractive index of benzene=1.5=speed of light in vaccum/speed of light in benzene.
c/v=1.5. v=2/3c
Percentage reduce in speed of light=(c-v/c)*100
=(1/3)*100=33.33%
it may be correct r wrong
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