Question

what is the percentage of S by mass in SO2(O=16,S=32) options are 50%,33%,66% and 25%

Answer 1

Answer:

mass of SO2 =64g

% of S=32/64*100

=50%

The answer is 50%

Answer 2

Answer:

=> mass of S in one molecule of SO2

= 32 a.m.u.

=> mass of one molecule of SO2

= (32+2×16) a.m.u.

= ( 32+32 ) a.m.u.

= 64 a.m.u.

{ where a.m.u. is atomic mass unit}

now, percentage of S by mass in SO2

= (32/64) × 100%

= 50%

I hope it would help you

thank you.