Question

What is the percentage of sulphur in H2S2O7

Answer 1

Answer:

The percentage of Sulphur in H²S²O7 is 18.18%

Answer 2

The mass percent of sulfur in compound is 35.96 %

Explanation:

To calculate the mass percentage of sulfur in compound, we use the equation:

$\text{Mass percent of sulfur in compound}=\frac{\text{Mass of sulfur}}{\text{Mass of compound}}\times 100$

Mass of sulfur in compound = (2 × 32) = 64 g

Mass of the compound, $(H_2S_2O_7)=[(2\times 1)+(2\times 32)+(7\times 16)]=178g$  

Putting values in above equation, we get:

$\text{Mass percent of sulfur in compound}=\frac{64g}{178g}\times 100=35.96\%$

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