What is the percentage probability that a point chosen randomly from the interior a rectangle is closer to the rectangle's center than to it's vertices?
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0
Answer:
4
–
1
Step-by-step explanation:
consider the radius of circle as r, then the points closer to center than boundary will lie within the radius of r/2. So the favorable outcomes would be the points inside the area of circle with radius r/2, whereas the total possible outcomes would be all the points inside the area of circle with radius r.
Therefore the probability is P(E)=
πr
2
πr
2
/4
=
4
1
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