Question

what is the percentage reduction in heat transfer if 7 shields of same emissivities as the bodies are placed in between them. solved answer free

Answer 1

THE ANSWER IS 87.5%

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Answer 2

The percentage reduction in heat transfer if 7 shields of same emissivities as the bodies are placed in between them is 87.5%.

1) We know,

    ( Heat transfer without shield / Heat transfer with shield ) = (1/ n+1)

here, n is the number of radiation shields that are placed in between the two plates. So, n = 7

2) So, ( Heat transfer without shield / Heat transfer with shield ) = 1/8

3) Now, Percentage reduction in heat transfer = (Heat transfer with shield - Heat transfer without shield) / Heat transfer with shield *100

4) So, Percentage reduction in heat transfer = (1-1/8) * 100 = 87.5 %