Question

what is the perimeter?​

Answer 1

Answer:

perimeter is the boundary or a size of the boundry

Answer 2

Given :-

⎊ Area of the rhombus = 24 cm²

⎊ One of it's diagonal = 8 cm

To Find :-

⎊ Perimeter of this rhombus

Solution :-

⎊ As we know that

$\sf \rightarrow Area\;of\;rhombus\;=\;\dfrac{1}{2} \times \sf D_1 \times \sf D_2$

$\sf Where,\\\\D_1 = 1^{st} Diagonal \\\\D_2 = 2^{nd} Diagonal$

$\sf \implies 24\;cm^{2} = \dfrac{1}{2} \times 8 \times D_2$

$\sf \implies D_2 = \dfrac{24}{4} = 6\;cm$

⎊ As we know that ,

Diagonals bisect each other

∴  $\sf AO = \dfrac{8}{2} = 4\;cm$

∴ $\sf BO = \dfrac{6}{2} = 3\;cm$

⎊ We need to find the side length now

According to the Pythagoras theorem

⇢ AB² = AO² + OB²

⇢ AB² = 3² + 4²

⇢ AB = √3²+4²

⇢ AB = √25

⇢ AB = 5 cm

⎊ Now , we need to find the perimeter :

Perimeter of a rhombus = 4 × Side

⇒   4 × 5

⇒   20 cm

∴ Perimeter of this rhombus is 20 cm