what is the perimeter and area of length 8m, breadth 9dm
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Answered by
38
as we know one decimeter(dm) is equals to
0.1m.
Now
length of rectangle = 8m
breadth of rectangle =0.9m
perimeter of rectangle = 2(l+b)
= 2(8+0.9)
=2×8.9
=17.8m
area of rectangle = l×b
= 8×0.9
=7.2m^2.
we can also calculate it in dm (decimeter)
As
8 metre is equals to 80 decimeter
so
length of rectangle = 80 dm
breadth of rectangle = 9 dm
perimeter of rectangle
=2(l+b)
=2(80+9)
=2×89
=178dm
area of rectangle = l×b
= 80 × 9
=720dm^2
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1
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