Question

What is the perimeter of a rectangle having length of 25 cm and breadth of 19 cm
A) 475 cm
B)176 cm
C)88 cm
D)44 cm ​

Answer 1

Answer:

C is the answer

Step-by-step explanation:

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Answer 2

Answer:

★ Given

${ \implies\rm{Length \: of \: Rectangle = 25 cm }}$

${\implies\rm{Breadth \: of \: Rectangle = 19 cm}}$

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★ To Find

$\implies \rm{Perimeter \: of \: Rectangle }$

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★ Using Formula

${ \implies\rm{Perimeter \: of \: Rectangle=2(Length + Breadth)}}$

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★ Solution

${\implies \rm \bf \red{Perimeter \: of \: Rectangle =2(25 + 19)}}$

${\implies\rm \mathbf \red{Perimeter \: of \: Rectangle =2 \times 44}}$

${\implies \rm \bf \red{Perimeter \: of \: Rectangle =88 \: cm}}$

$\large\boxed{\bf \pink{P{\mathfrak \pink{erimeter = 88 cm}}}}$

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Therefore

The option (C) is the correct answer. ✔

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More Useful formulae

$\bigstar \: \rm{Area \: of \: Rectangle =Length × Breadth}$

$\bigstar \: \rm{Diagonal \: of \: Rectangle = \sqrt{ {Length }^{2} + { Breadth}^{2} } }$

$\bigstar \: \rm{Area \: of \: Square } = {a}^{2}$

$\bigstar \: \rm{Perimeter \: of \: Square = 4a }$

$\bigstar \: \rm{Diagonal \: of \: Square = a \sqrt{2} }$