Question

What is the perimeter of a rectangle whose length is 17m and area is 221 sq.M?

Answer 1

Solution:-

Given:-

Length of Rectangle = 17m

Let the breath be "x"m.

Now,

Area = Length × Breadth

=> 221 = 17 × x

=> x = 221/17

=> x= 13m.

Hence,

Perimeter = 2( length + Breadth)

=> Perimeter = 2 ( 17 + 13)

=> Perimeter = 2 × 30

=> Perimeter = 60m.

Answer 2

Perimeter=2(Length+Breadth)

Area=Length×Breadth

Given Length=17 m

Let Breadth=x m

Area=221 m²

A/Q

LENGTH×BREADTH=AREA

17×X=221

X=221/17

X=13 M

BREADTH=X=13 M

So we got

Length=17m

Breadth=13 m

Perimeter=2(l+b)

=2(17+13) m

=2×30 m

=60 m

$\boxed{\mathbf{\huge{Perimeter=60\:m}}}$