Question

What is the perimeter of a rectangle with length 0.42m & breadth 31.5cm?​

Answer 1

Step-by-step explanation:

perimeter of a rectangle = 2(l+b)

where, b = breadth = 31.5

l = length = 0.42

2(L+b)

2(0.42+31.5)

2(31.92)

63.84

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Answer 2

Given:-

Length = 0.42 m

Breadth = 31.5 cm

To find:-

Perimeter of the rectangle = ?

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(Both the units should be same. So,covert anyone...)

Length = 0.42 m

As we know,

1 m = 100 cm

Multiply the given value by 100.

$\dfrac{42}{100} \times 100$

$=42 cm$

Length = 42 cm

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Solution:-

Formula to find perimeter of a rectangle

Perimeter = 2(l+b)

Put the given values.

= 2(42+31.5)

= 2(73.5)

= 147 cm

Perimeter of the rectangle = 147 cm

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Some Related formulas

▪Area of rectangle = $length \times breadth$

▪ Diagonal = $\sqrt{w^2 + l^2}$