What is the perimeter of a rhombus whose diagonals are 10 cm and 24 cm ?
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Answered by
4
perimeter of rhombus = 52 cm
steps : using pythagoras theorem
the hypotenuse = √10 ² + √12 ²
= √169
= 13 cm
perimeter = 4s
= 4 × 13
= 52 cm
steps : using pythagoras theorem
the hypotenuse = √10 ² + √12 ²
= √169
= 13 cm
perimeter = 4s
= 4 × 13
= 52 cm
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Answered by
3
p diagonal=10cm
q diagonal=10cm
s = side = 1/4 perimeter.
(1/2 one diagonal )^2 + (1/2 2nd diagonal)^2 = s^2
(24/2)^2 + (10/2)^2 = s^2
(12)^2 + (5)^2 = s^2
169 = s^2
s = 13= 1/4 perimeter
perimeter = 52
q diagonal=10cm
s = side = 1/4 perimeter.
(1/2 one diagonal )^2 + (1/2 2nd diagonal)^2 = s^2
(24/2)^2 + (10/2)^2 = s^2
(12)^2 + (5)^2 = s^2
169 = s^2
s = 13= 1/4 perimeter
perimeter = 52
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