What is the perimeter of a sector of angle 45° of a circle with radius 7 cm?
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Let us consider a circle with radius 7 cm.
We can find its circumference by simple formula 2×π×r. In our case, r=7. Hence we get,
C=2×π×7= 2×22/7×7 =2×22 =44.
Now, a circle is 360°. If I want to find the length of the arc of a sector of angle 45°, we devide C by 8. We get,
C÷8=44÷8=5.5
This is the length of the arc. Now, to get complete perimeter, we add the radius 2 times. Hence we get,
5.5+2×r=5.5+2×7=5.5+14=19.5
This is the perimeter of the sector of the circle with radius 7 and angle 45°.
I hope this helps l
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