Question

What is the perimeter of a sector of angle 90^0 of a circle with radius 7 cm?

Answer 1

Answer:

The answer is 25cm.

Step-by-step explanation:

Perimeter of sector of a circle = 2r + 2πr* Ф/360°

By substituting the values, we get:

⇒ 2*7 + 2 * 22/7 * 7 * 90°/360°

⇒ 14 + 2 * 22 * 1/4

By taking LCM as 4, we get:

⇒ 56 + 44 / 4

⇒ 100/4

⇒ 25