What is the perimeter of a square with side (2a + 3b)?
Answers
We know that all the sides of a square are equal.
Perimeter of a Square
Perimeter of the square ABCD
= AB + BC + CD + AD
= 2 cm + 2 cm + 2 cm + 2 cm
= (2 × 4) cm
= 8 cm
Perimeter of a square is 4 times of s side.
Perimeter of a square = 4 × length of a side.
Given,
A square with a side (2a+3b)
To find,
The perimeter of a square.
Solution,
The perimeter of the given square with side (2a+3b) is 8a+12b.
We can easily solve the mathematical problem by the following procedure.
We know that;
A perimeter is the sum of all the sides of a closed figure. As a square has all its four sides equal, its perimeter is just simply four times the length of one of its sides.
It is given that one side of a square is (2a+3b).
Thus,
∴ The perimeter of a square = 4(2a+3b)
= 8a + 12b
As a result, the perimeter of the given square with side (2a+3b) is 8a+12b.