what is the perimeter of a triangle sides =1. 7x2-7xy+8 2. 7xy-7xy-3 3. x-3-8xy+5
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1.(x2-5x+6)(2x+7)
(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)
(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)=x2-3x+13
2.4x2 – 3x + 7
4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x°
4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x° ∵ All the exponents of x are whole numbers ∴ 4x2 – 3x + 7 is a polynomial in one variable.
3.(a - b)3 = a3 - b3 - 3ab(a - b). 5. (a + b + c)2 = a2 + b2 + c2 +2ab+2bc +2ca.
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Answer:
First side = 7x²–7xy+8
Second side = 7xy–7xy–3
Third side = x–3–8xy+5
Perimeter = summ of all the three sides
Therefore, P = 7x²–7xy+8+(7xy–7xy–3)+(x–3–8xy+5)
P = 7x²–7xy+8+(–3)+(x–8xy+2)
P = 7x²–7xy+8–3+x–8xy+2
P = 7x²–15xy+7
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