What is the Perimeter of a triangle with vertices (0,4)(0,0)
and(3,0) ?
Answers
Answered by
0
Answer:
Let ABC be a triangle having A(0,4);B(0,0);C(3,0)
Using distance formula, we get
AB= square root (0−0) 2+(0−4) 2 = 16 =4
BC=square root (3−0) 2 +(0−0) 2 = 9=3
CA= square root(0−3) 2 +(4−0) 2= 25=5
Perimeter of △ABC=AB+BC+CA=4+3+5=12
please mark my answer as Brainliest and follow me
Answered by
3
Answer:
12
Step-by-step explanation:
Let ABC be a triangle having A(0,4);B(0,0);C(3,0)
Let ABC be a triangle having A(0,4);B(0,0);C(3,0) Using distance formula, we get
AB= √(0−0)²+(0−4) ²= √16 =4
BC= √(3−0)²+(0−0)²= √9 =3
CA= (0−3)² +(4−0)² = √25=5
Perimeter of △ABC=AB+BC+CA=4+3+5=12
Perimeter of △ABC=AB+BC+CA=4+3+5=12solution
Attachments:
Similar questions