Question

what is the perimeter of an isosceles triangle whose base is 5 metre and two equal side are 6 metre​

Answer 1

Step-by-step explanation:

PERIMETER IS THE SUM OF ALL SIDES i.e, AB +BC + AC

SO, PERIMETER OF THE ∆ ABC WILL BE,

$= 5 + 6 + 6$

$= 5 + 12$

$= 17 \: m$

Answer 2

Step-by-step explanation:

5+6+6 - 17

hopes it helps