what is the perimeter of rectangle whose area is (x²-×-42 ) sq. units ?
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Answer:
perimeter =4x-2 units
Step-by-step explanation:
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Step-by-step explanation:
Let the lenghth of the required rectangle be l unit and breadth be b unit.
Area of the rectangle =lb unit²
A/q, x² - x -42= lb
or, x²-(7-6)x-42=lb
or, x²-7x+6x-42=lb
or, x(x-7)+6(x-7) = lb
or,. (x+6)(x-7)=lb
Therefore, length=x+6 and breadth = x-7
Now,
perimeter of the rectangle = 2(l+b)
=2(x+6+x-7).
=2(2x-1)
=4x-2.
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