Question

what is the perimeter of rectangle,whose lenght is 17m and area is 221sq meter​

Answer 1

Step-by-step explanation:

Area of rectangle= l×b

221=17×b

221/17 = b

13m = b

perimeter of rectangle = 2(l+b)

=2(17+13)

= 60m

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Answer 2

Answer:

Solution:

Area of the rectangle = 221sq.m

Length of it = 17m

Breadth of it = Area÷Length

= 221sq.m÷17m

=13m

Perimeter of it = 2(l+b)

=2(17+13)m

= 2×30m

= 60m

Therefore, the perimeter of the rectangle is 60m.(Answer)