Question

What is the perimeter of rectangle whose length is 8 cm and and

diagonal is 10 cm​

Answer 1

The length of a rectangle is 8 cm and each of its diagonals measures 10 cm. Find its breadth

Let ABCD be the given rectangle in which length AB = 8 cm and diagonal AC = 10 cm.

Since each angle of a rectangle is a right angle,

we have ∠ABC = 900 .

From right angled triangle ABC , we have

AB2 + BC2 = AC2

⇒BC2 = AC2 - AB2 = {(10)2 -(8)2} = (100 - 64) = 36

⇒BC = = 6 cm.

Hence , breadth = 6 cm.

Answer 2

Answer:

Perimeter = 28 cm

Step-by-step explanation:

sq. root of 10(10)-8(8)

sq. root of 100-64

sq. root of 36=6

therefore the perimeter is 2(8+6)

2*14

=28