Question

What is the perimeter of sector with radius 10.5 cm and sector angle 60?

Answer 1

Answer:

From the data given in the question we know that

radium is equal to the= r = 10.5 cm and the angle is equal to = x = 60 degree .

so the formula for finding perimeter of angle 60 degree = length of arc +2*radius

so the perimeter will be =(x/360°) 2πr + 2r

By putting the values we will got = (60°/360°)( 2 *3.14 * 10.5) + 2* 10.5

So upon solving the perimeter of sector will be = 32 cm. which is our answer here.

explanation:-

Given :- Radius = 10.5 cm and Sector angle = 60°

Perimeter of a sector of a circle = [(theta/360°)*2πr] + (2r)

⇒[(60/360)*2*22/7*10.5] + (2*10.5)

⇒ 1*462/6*7 + 21

⇒ 462/42 + 21

⇒ 11 + 21

⇒ 32 cm

So, the perimeter of sector is 32 cm

Answer 2

Here is your answer user.