Question

What is the perimeter of the rectangle ABCD when AD = 3 and BD = 5

Answer 1

2(5+3)=16 ok follow me i hope it will help u

Answer 2

AD=3 that is breadth and BD=5that is diagonal
By using Pythagoras theorem,
h^2=p^2+b^2
(5)^2=(3)^2+b^2
25=9+b^2
25-9=b^2
16=b^2
root 16=b
4=b
Now length is 4
Perimeter of rectangle=2(l+b)
=2(4+3)
=2 x 7
=14
Hope my answer will help you...