Question

what is the perimeter of the rectangle whose length is 1225 cm and breadth is 1 metre​

Answer 1

Step-by-step explanation:

$\huge\fcolorbox{black}{green}{Given}$

Length = 1225m

Breadth = 1m

$\huge\fcolorbox{black}{green}{Formula Used}$

Perimeter of Rectangle = 2 ( L + B )

$\huge\fcolorbox{black}{green}{Solution}$

• 2 ( 1225 + 1 )

• 2 ( 1226 )

• 2412m..

Answer 2

Step-by-step explanation:

We have;

$l = 1225 \: cm$

$b = 1 \: m = 100 \: cm$

we know that; perimeter of rectangle is

$2(l + b)$

so here, perimeter of the rectangle is

2(1225+100) = 2×1325 = 2650

hope it helps you

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