what is the perimeter of the Rhombus pqrs consider the Rhombus shown in a shown in the figure PR equal to 10 cm and SQ equal to 24 cm which are the diagonals
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By the Pythagorean theorem, we find that each of the sides of the rhombus is √([7.5)² + (4)²] = √[56.25 + 16] = √72.25 = 8.5 cm. The perimeter of the rhombus is four times the length of one side: 34 cm
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