Question

What is the perimeter of the sector with radius 10.5cm and sector angle 60°?

Answer 1

From the data given in the question we know that
radium is equal to the= r = 10.5 cm and the angle is equal to = x =  60 degree .
so the formula for finding perimeter of angle 60 degree  = length of arc +2*radius
 so            the perimeter will be    =(x/360°) 2πr + 2r
By putting the values we will got = (60°/360°)( 2 *3.14 * 10.5) + 2* 10.5
  So upon solving  the perimeter of sector will be = 32 cm. which is our answer here.

Answer 2

Solution :-

Given :- Radius = 10.5 cm and Sector angle = 60°

Perimeter of a sector of a circle = [(theta/360°)*2πr] + (2r)

⇒[(60/360)*2*22/7*10.5] + (2*10.5)

⇒ 1*462/6*7 + 21

⇒ 462/42 + 21

⇒ 11 + 21

⇒ 32 cm

So, the perimeter of sector is 32 cm

Answer.