What is the perimeter of the square ABCD in the adjoining figure
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first find DC
therefore in triangle FEC by Pythagores. theorem
10²=6²+EC²
100=36+EC²
100-36=EC²
64. = EC²
√64=EC
8=EC
therefore DC=2+8=10
perimeter of circle =4× side
=4×10
= 40
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