What is the perimeter of triangle who's sides are 51/2cm 73/4cm 31/4 cm?
Answers
Answered by
0
let sides of triangle
a= 51/2 cm
b= 74/ 4cm
c= 31/4 cm
now perimeter of triangle= a+ b+ c
perimeter of triangle=(51/2 +74/4+31/4) cm
= (2× 51+74+31)4
=(102+74+31)4
=207/4=51.75cm ans.
Similar questions