what is the perimeter of triangle with side 3i+4j+5k , 4i-3j-5k and 7i+j
Answers
Answered by
5
the perimeter, P, of a triangle is given by the formula
P = a + b + c
where a, b and c are the side lengths of the triangle
where P=(3i+4j+5k)+(4i-3j-5k)+(7i+j+0k)
=(14i+2j)
=2(7i+j)
P = a + b + c
where a, b and c are the side lengths of the triangle
where P=(3i+4j+5k)+(4i-3j-5k)+(7i+j+0k)
=(14i+2j)
=2(7i+j)
janhavi4:
answer should be in root
Answered by
4
perimeter of a triangle = a+b+c where a,b,c are the three sides of the triangle.
a= 3i+4j+5k
b= 4i-3j-5k
c= 7i +j
perimeter = (3i+4j+5k)+(4i-3j-5k)+(7i+j)
= 3i+4j+5k+4i-3j-5k+7i+j
= 14i + 2j
hope it helps!!!!
a= 3i+4j+5k
b= 4i-3j-5k
c= 7i +j
perimeter = (3i+4j+5k)+(4i-3j-5k)+(7i+j)
= 3i+4j+5k+4i-3j-5k+7i+j
= 14i + 2j
hope it helps!!!!
Similar questions