What is the perimetre of the sector with radius 10.5 cm and sector angle 60
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hi yusuf,
perimeter of sector = 2*radius + length of arc
now
2*radius = 2*10.5 = 21cm
length of arc
= perimeter of circle * Ф/360
= 2πr * 60/360
= 2*22/7*10.5*1/6
= 11 cm
hence
perimeter of sector
= 2*radius + length of arc
= 21 + 11
= 32 cm
so perimeter of given sector = 32 cm
Hope it helped.
Let me know if any doubts.
Cheers !!!
perimeter of sector = 2*radius + length of arc
now
2*radius = 2*10.5 = 21cm
length of arc
= perimeter of circle * Ф/360
= 2πr * 60/360
= 2*22/7*10.5*1/6
= 11 cm
hence
perimeter of sector
= 2*radius + length of arc
= 21 + 11
= 32 cm
so perimeter of given sector = 32 cm
Hope it helped.
Let me know if any doubts.
Cheers !!!
jish4you:
hope u liked my solution
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