what is the period of a pendulum of length 2.45 metres. (g=9.8 m/s² and π=3.14)
Answers
Answered by
4
Use the formula,
T = 2 pi root over l/g
Here l is length
g is acceleration due to the gravity
T is time period.
Substitute values to get your answer.
T = 2 pi root over l/g
Here l is length
g is acceleration due to the gravity
T is time period.
Substitute values to get your answer.
Answered by
3
T = 2 π sqrt(L/g)
= 2 × 3.14 × √[(2.45 m) / (9.8 m/s²)]
= 3.14 seconds
Period of pendulum is 3.14 seconds.
= 2 × 3.14 × √[(2.45 m) / (9.8 m/s²)]
= 3.14 seconds
Period of pendulum is 3.14 seconds.
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