What is the perpendicula distance betuween the e and the turning point if of to in produces force 50 a of force a of moment 2.5. Nm
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Explanation:
F=525N
τ=420N−m
Moment of force
=Force× Perpendicular distance
∴420N−m=525N× Perpendicular distance.
∴ Perpendicular distance
=
525
420
=0.8m
0.8 m is the shortest distance between the point of application of force and the turning point
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